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  •  25% of a zero order reacton completes in 4 hours. 12.5% of the same reaction completes inOption: 1 6&nb

 25% of a zero order reacton completes in 4 hours. 12.5% of the same reaction completes in

Option: 1

6 hours


Option: 2

4.6 hours


Option: 3

8 hours


Option: 4

2 hours


Answers (1)

best_answer

For a zero order reaction,
Rate constant,  \mathrm{K=\frac{[A]_0-[A]}{t}}  where,
\mathrm{[A]_0=} initial concentration of reactant
\mathrm{[A]=} concentration of reactant at time ' t '
when 25 % of a zero order reaction completes,

\mathrm{[A]=\frac{75[A]_0}{100}

Rate constant, \mathrm{(K)=\frac{[A]_0-\frac{75}{100}[A]_0}{4}=0.0625[A]_0}
When 12.5 % of the reaction completes,

\mathrm{ {[A]=\frac{87.5[A]_0}{100}} }

\mathrm{ \text { Rate constant, }(K)=\frac{[A]_0-\frac{87.5}{100}[A]_0}{t} \\ }

\mathrm{ t=\frac{[A]_0-\frac{87.5}{100}[A]_0}{K} \\ }

\mathrm{ t=\frac{0.125[A]_0}{0.0625[A]_0} \\ }

\mathrm{ t=2 \text { hours } }.
 

Posted by

manish painkra

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