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  • 74.5 g of a metallic chloride contain 35.5 g of chlorine. The equivalent weight of the metal isOption: 1 19.5<s

74.5 g of a metallic chloride contain 35.5 g of chlorine. The equivalent weight of the metal is

Option: 1

19.5


Option: 2

35.5


Option: 3

39


Option: 4

78


Answers (1)

best_answer

74.5 g of a metallic chloride contain 35.5 g of chlorine. 

Therefore, weight of other element present in the chloride is 

= Weight of Metal Chloride  - Weight of Chloride

= 74.5 - 35.5 = 39 g

Thus, 39 g of the metal combines with 35.5 g of Chlorine

Mole of Chloride present = weight/molar mass = 35.5/35.5 = 1 mole

So, one mole of Cl is present and we know the charge on Cl is (-1).

So, MCl configuration will be there where M-metal.

MCl = M++ Cl-

So, one mole of Metal will be present and the charge would be (+1) on metal.

Molecular weight = mass of 1 mol metal = 39 g

Equivalent Weight = Molecular weight/ Valency.

Equivalent Weight =  39/1 =39

hence, the equivalent weight of the metal is 39.

Therefore, the correct option is (3)

Posted by

Pankaj Sanodiya

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