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A 15 Amp circuit breaker trips in home when the current through it reaches 8 Amp. What is the minimum number of 100 watt light bulb operated at 100 volts in home that will cause it to the trip.
Option: 1
2

Option: 2
4

Option: 3
6

Option: 4
8

Answers (1)

best_answer

Current through one bulb $=\frac{100}{100}$

$8=N\times \frac{100}{100}$

$N=8$

where N – Number of bulbs.

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Deependra Verma

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