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A 16 cm^3 volume of water flows per second through a capillary tube of radius r cm and length l cm, when connected to a pressure head of h cm of water. If a tube of the same length and radius r/2 is connected to the same pressure head, find the mass of water flowing per minute through the tube:

Option: 1

40 g/min


Option: 2

52 g/min


Option: 3

60 g/min


Option: 4

70 g/min


Answers (1)

best_answer

Using

 Q = \frac{\prod \rho r^4}{8\eta ^e }

\frac{Q' }{Q}= \frac{(\frac{r}{2})^4}{r^4 }

Q' = \frac{1}{16} Q = \frac{1}{16} * 16

Q' = 1 cm^3/sec

\therefore Mass = PQ'

                   1 * 1 = 1 g/sec

The mass of the water flowing per minute

                = 1 * 60 g/sec

                = 1 * 60 g/sec= 60 g/sec

Posted by

Nehul

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