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  • A 50 Hz AC source of 20V is connected across R and C as shown in figure. The voltage across R is 12V. The voltage across C is <img alt="" src="https://cdn.entrance360.com/media/uploads/20

A 50 Hz AC source of 20V is connected across R and C as shown in figure. The voltage across R is 12V. The voltage across C is

Option: 1

8V


Option: 2

16V


Option: 3

10V


Option: 4

not possible to determine unless values of R and C are given


Answers (1)

best_answer

The given circuit is a C-R series circuit,\mathrm{V_R}s in phase with i, while VC lags behind i by \mathrm{90^{\circ} \text {. }} Hence, resultant potential is \mathrm{V=\sqrt{V_R^2+V_C^2}}

\mathrm{\begin{array}{ll} \therefore & (20)^2=(12)^2+V_c^2 \\ \Rightarrow & V_c^2=(20)^2-(12)^2=400-144=256 \\ \Rightarrow & V_c=\sqrt{256}=16 \mathrm{~V} \end{array}}

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Sayak

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