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  • A ball is released from the top of a tower of height metre. It takes <img alt="T" src="https://learn.careers360.com/latex-image/?T"

A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What  is the position of the ball in   T/3 second?

Option: 1

h/9  metre from the ground


Option: 2

7h/9 metre from the ground


Option: 3

8h/9 metre from the ground


Option: 4

17h/18 metre from the ground


Answers (1)

best_answer

Equation of motion s= ut+\frac{1}{2}gt^{2}

\therefore \: \: h=0+\frac{1}{2}gT^{2}

or\: \: \: 2h= g T^{2}\cdots \cdots \cdots \left ( i \right )

After T/3 \: \: sec,

s= 0+\frac{1}{2}\times g\left ( \frac{T}{3} \right )^{2}= \frac{gT^{2}}{18}

or\: \: 18\: s= gT^{2}\cdots \cdots \cdots \left ( ii \right )

From (i) and (ii)

18\: s= 2h

or\: \: s= \frac{h}{9}m\: \: from \: the\: top

\therefore \: \: \: Height \: from\: ground= h-\frac{h}{9}= \frac{8h}{9}m

 

Posted by

vishal kumar

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