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A ball of mass $\mathrm{0.15 \mathrm{~kg}}$ hits the wall with its initial speed of $\mathrm{12 \mathrm{~ms}^{-1}}$ and bounces back without changing its initial speed. If the force applied by the wall on the ball during the contact is $\mathrm{ 100 \mathrm{~N}, }$ calculate the time duration of the contact of ball with the wall.
Option: 1
$\mathrm{0.018 \mathrm{~s}}$

Option: 2
$\mathrm{0.036 \mathrm{~s}}$

Option: 3
$\mathrm{0.009 \mathrm{~s}}$

Option: 4
$\mathrm{0.072 \mathrm{~s}}$

Answers (1)

best_answer

$\mathrm{\Delta p =p_f-p_i }$

$\mathrm{=(-m v)-(+m u) }$

$\mathrm{=(-m v-m u) }$

$\mathrm{v =u=12 \mathrm{~m} / \mathrm{s} \quad(\text { Given }) }$

$\mathrm{\Delta p =-0.15(12+12) }$

$\mathrm{\Delta p =-3.6 }$

$\mathrm{F =\frac{\Delta p}{\Delta t} }$

$\mathrm{100 =\frac{3.6}{\Delta t} }$

$\mathrm{\Delta t =0.0369}$

Hence (2) is correct option.

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Nehul

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