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A bar magnet of magnetic moment 3.0A - m^{2} is placed in a uniform magnetic induction field of  2\times 10^{-5}T . If each pole of the magnet experiences a force of 6\times 10^{-4}N  , the length of the magnet is

Option: 1

0.5 m


 


Option: 2

0.3 m


Option: 3

0.2 m


Option: 4

0.1 m


Answers (1)

best_answer

As we learned

 

Magnetic field -

B=\frac{F}{m_{0}}

=B=\frac{\mu _{0}}{4\pi } \frac{m}{d^{2}}

 

-

 

 f=mB\Rightarrow f=\frac{M}{L}\times B

\Rightarrow 6\times 10^{-4}=\frac{3}{L}\times 2\times 10^{-5}\Rightarrow L=0.1m

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mansi

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