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 A batch of one hundred bulbs is inspected by testing four randomly chosen bulbs. The batch is rejected if even one of the bulbs is defective. \mathrm{A} batch typically has five defective bulbs. The probability that the current batch is accepted is

Option: 1

0.8119


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

The required probability,
\text { i. } \mathbf{p}=\frac{{ }^{95} \mathrm{C}_{4}}{{ }^{100} \mathrm{C}_{4}}

[\because  batch will be accepted only when all the four bulbs come out from non-defective bulbs. Here defective bulbs = 5 & non-defective bulbs = 95.]

=\frac{95 \times 94 \times 93 \times 92}{100 \times 99 \times 98 \times 97}
=0.8119


 

 

Posted by

Divya Prakash Singh

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