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A block of $\sqrt{3} \mathrm{~kg}$ is attached to a string whose other end is attached to the wall. An unknown force $\mathrm{F}$ is applied so that the string makes an angle of $30^{\circ}$ with the wall.The tension $\mathrm{T}$ is: (Given $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )

Option: 1
$20 \mathrm{~N}$

Option: 2
$10 \mathrm{~N}$

Option: 3
$15 \mathrm{~N}$

Option: 4
$25 \mathrm{~N}$

Answers (1)

best_answer

$\mathrm{F}=\operatorname{Tsin} 30^{\circ}$

$\sqrt{3} g=\mathrm{T} \cos 30^{\circ}$
$\tan 30^{\circ}=\frac{F}{\sqrt{3}} g$

$\frac{1}{\sqrt{3}}=\frac{F}{\sqrt{3} g}$
$\mathrm{F}=10 \mathrm{~N}$
$\mathrm{T}=\frac{\mathrm{F}}{\sin 30^{\circ}}=10 \times 2$
$\mathrm{T}=10 \times 2=20 \mathrm{~N}$

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Nehul

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