Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A block of mass 1kg is at rest on a rough horizontal surface having coefficient of static friction 0.2 and kinetic friction 0.15, find the friction force (in Newtons) if horizontal force of 2.

A block of mass 1kg is at rest on a rough horizontal surface having coefficient of static friction 0.2 and kinetic friction 0.15, find the friction force (in Newtons) if horizontal force of 2.5N is applied on block - 

(g=9.8m/s2)

Option: 1

1.47


Option: 2

2.5


Option: 3

1.7


Option: 4

2.3


Answers (1)

best_answer

As we learn

Friction -

Opposing Force which is parallel to the surface and opposite to direction of Relative Motion.

- wherein

Direction of friction is always opposite the direction of Relative Motion.

 

 

fext.=2.5N

Fl = 0.2 * 1 * 9.8 = 1.96N

\because f_{ext}>F_{l}

body will be in moving condition

friction force,

F_{k} = \mu _{k}N = \mu _{k} mg = 0.15 * 1 *9.8 = 1.47N

 

Posted by

avinash.dongre

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question