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A block of mass ' \mathrm{m} ' (as shown in figure) moving with kinetic energy E compresses a spring through a distance 25 \mathrm{~cm} when, its speed is halved. The value of spring constant of used spring will \mathrm{nE}\: \: \mathrm{Nm}{ }^{-1} \text { for } \mathrm{n}=_____________.

Option: 1

24


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

If the speed is halved, the kinetic energy will be \mathrm{\frac{1}{4}^{th}}

\mathrm{E =P E+K E }

\mathrm{E =P E+\frac{E}{4} }

\mathrm{\frac{3 E}{4} =\frac{1}{2} k x^2 }

\mathrm{k=\frac{3E}{2x^{2}}=\frac{3E}{2\times\left ( \frac{1}{4} \right )^{2}}}

\mathrm{K =24 E }

\mathrm{\therefore n=24}







 

Posted by

manish painkra

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