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A block of mass $\mathrm{200g}$ is kept stationary on a smooth inclined plane by applying a minimum horizontal force $\mathrm{F=\sqrt{xN}}$ as shown in figure.

The value of $\mathrm{x=}$ _________________.
Option: 1
12

Option: 2
-

Option: 3
-

Option: 4
-

Answers (1)

best_answer

$\mathrm{N=m g \cos 60^{\circ}+F \sin 60^{\circ}}\\$

For stationary block

$\mathrm{F \cos 60^{\circ}=m g \sin 60^{\circ}}\\$

$\mathrm{\sqrt{x}=2 \times \sqrt{3}} \\$

$\mathrm{x=12}$

Posted by

sudhir.kumar

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