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  • A block of mass M placed inside a box descends vertically with acceleration 'a'. The block exerts a force equal to one-fourth of its weight on the floor of the box.

A block of mass M placed inside a box descends vertically with acceleration 'a'.

The block exerts a force equal to one-fourth of its weight on the floor of the box.

The value of 'a' will be

Option: 1

\mathrm{\frac{g}{4}}


Option: 2

\mathrm{\frac{g}{2}}


Option: 3

\mathrm{\frac{3g}{4}}


Option: 4

\mathrm{g}


Answers (1)

best_answer

FBD wrt ground frame

\mathrm{M g-N=M a} \\

\mathrm{N=M g-M a-\text { (i) }} \\

\mathrm{\text { Given } N=\frac{M g}{4}-\text { (ii) } }\\

\mathrm{M a=M g-\frac{M g}{4}=\frac{3 M g}{4}} \\

\mathrm{a=\frac{3 g}{4}}

Hence correct  option is 3

Posted by

Rakesh

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