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A block of mass \mathrm{10 \mathrm{~kg}} starts sliding on a surface with an initial velocity of \mathrm{9 .8 \mathrm{~ms}^{-1}.} The coefficient of friction between the surface and block is \mathrm{0 .5 .} The distance covered by the block bofore coming to rest is:
\mathrm{\left [ use\: g= 9.8\: ms^{-2} \right ] }

Option: 1

\mathrm{4.9\, m}


Option: 2

\mathrm{9.8\, m}


Option: 3

\mathrm{12.5\, m}


Option: 4

\mathrm{19.6\, m}


Answers (1)

best_answer


\mathrm{f= \mu N= \mu m g}
\mathrm{a= \mu g= 4.9\, m/s^{2}}

\mathrm{V^{2}= u^{2}+2as}
\mathrm{0= \left ( 9.8 \right )^{2}+2\left ( -4.9 \right )s}
\mathrm{s= 9.8\, m}

The distance covered by thr block before coming to rest is \mathrm{ 9.8\, m}

The correct option is (2)

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