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A blue transition metal salt X reacts with H_{2}S in acidic medium and gives a black precipitate Y, which is insoluble in aqueous solution of KOH. The same salt on reacting with KI in acidic medium produces a yellow solution and a white precipitate Z. What is X, Y and Z?

Option: 1

X=CuCl_{2}\; Y=CuS \; Z=Cul_{2}


Option: 2

X=CuSO_{4}\; Y=CuS \; Z=Cul_{2}


Option: 3

X=CuS\; Y=CuCl_{2} \; Z=Cu_{2}l_{2}


Option: 4

X=CuSO_{4}\; Y=CuS_{2} \; Z=Cu_{2}l_{2}


Answers (1)

best_answer

\mathrm{CuSO}_4+\mathrm{H}_2 \mathrm{~S} \rightarrow \text { CuS (black ppt) }+\mathrm{H}_2 \mathrm{SO}_4

\begin{aligned} & \mathrm{CuSO}_4+2 \mathrm{KI} \rightarrow \mathrm{CuI}_2+\mathrm{K}_2 \mathrm{SO}_4 \\ & 2 \mathrm{CuI}_2 \rightarrow \mathrm{Cu}_2 \mathrm{I}_2 \text { (White ppt) }+\mathrm{I}_2 \end{aligned}

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Rakesh

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