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  • A body cools from to <img alt="40^{\circ}C" src="https://entrancecorner.oncodecogs.com/gif.latex?

A body cools from 60^{\circ}C to 40^{\circ}C in 6 minutes.If,temperature of surroundings is 10^{\circ}C. Then, after the next 6 minutes, its temperature will be ^{\circ}C.

Option: 1

28


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

60^{\circ}C\underset{6min}{\rightarrow}40^{\circ}C\underset{6min}{\rightarrow}T                T_o=10^{\circ}C

\begin{aligned} & \frac{\Delta \mathrm{T}}{\Delta \mathrm{t}}=\mathrm{k}\left(\mathrm{T}-\mathrm{T}_0\right) \\ & \frac{(60-40)}{6 \mathrm{~min}}=\mathrm{k}[50-10] \\ & \text { And } \frac{(40-\mathrm{T})}{6 \mathrm{~min}}=\mathrm{K}\left[\frac{40+\mathrm{T}}{2}-10\right] \\ & (1) /(2) \\ & \frac{20}{40-\mathrm{T}}=\frac{40}{\left(\frac{40+\mathrm{T}-20}{2}\right)} \end{aligned}

\begin{aligned} & \frac{20}{40-T}=\frac{40 \times 2}{20+T} \\ & (20+T)=(40-T) 4 \\ & 20+T=160-4 T \Rightarrow S T=140 \\ & T=\frac{140}{5}=28^{\circ} \mathrm{C} \end{aligned}

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Kuldeep Maurya

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