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A body mass m = 10 kg is attached to one end of a wire of length 0.3m. The maximum angular speed ( in rad s-1) with which it can be rotated about its other end in space station is (Breaking stress of wire =4.8\times 10^7 Nm^{-2} and area of cross-section of the wire =10^{-2} cm^2) is:
Option: 1
Option: 2 8
Option: 3 6
Option: 4 1
 

Answers (1)

best_answer

 

\begin{aligned} \frac{F}{A} &=\frac{m v^{2}}{l A} \\ \Rightarrow v &=\sqrt{\frac{l F}{m} }=\sqrt{\frac{0.3}{10} \times 4.8 \times 10^{7} \times 10^{-6}} \\ &=\sqrt{3 \times 48 \times 10^{4} \times 10^{-6}}=1.2 \mathrm{m} / \mathrm{s} \\ \omega &=\frac{v}{l}=\frac{1.2}{0.3}=4 \mathrm{rad} / \mathrm{s} \end{aligned}

 

the correct option is (1). 

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avinash.dongre

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