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A body of mass $10 \mathrm{~kg}$ is moving with an initial speed of $20 \mathrm{~m} / \mathrm{s}$ . The body stops after $5 \mathrm{~s}$ due to friction between body and the floor. The value of the coefficient of friction is: (Take acceleration due to gravity $.g=10 \mathrm{~ms}^{-2}$ )
Option: 1
0.3

Option: 2
0.5

Option: 3
0.2

Option: 4
0.4

Answers (1)

best_answer

$\mathrm{v}=\mathrm{u}+\mathrm{at}$

$0=20-\mu g(5)$
$\mu=\frac{2}{5}=0.4$

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Shailly goel

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