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A body of mass M at rest explodes into three pieces, in the ratio of masses 1: 1: 2. Two smaller pieces fly off perpendicular to each other with velocities of 30 \mathrm{~ms}^{-1}$ and $40 \mathrm{~ms}^{-1} respectively. The velocity of the third piece will be :
 

Option: 1

15 \mathrm{~ms}^{-1}


Option: 2

25 \mathrm{~ms}^{-1}


Option: 3

35 \mathrm{~ms}^{-1}


Option: 4

50 \mathrm{~ms}^{-1}


Answers (1)

best_answer

Conservation of momentum,

\mathrm{\frac{m}{4} \times 30 i+\frac{m}{4} 30 J+\frac{m}{2} \overrightarrow{\text{v}}=0}

\begin{aligned} \\\mathrm{\vec{v} =-15 i-20 \dot{J}} \\ \end{aligned}

\begin{aligned} \mathrm{|\vec{v}| =\sqrt{15^{2}+20^{2}}=25 \mathrm{~m} / \mathrm{s}} \end{aligned}

Hence, Correct answer is Option (2)

Posted by

Ritika Harsh

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