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  • A body weighs 250N in air, 200N in water amd 150N in liquid. Find density of liquid (density of water 1000kg/)<div c

A body weighs 250N in air, 200N in water amd 150N in liquid. Find density of liquid (density of water 1000kg/m^3)

Option: 1

4000 kg/m^3


Option: 2

1000 kg/m^3


Option: 3

2000 kg/m^3


Option: 4

1050 kg/m^3


Answers (1)

best_answer

\frac{\rho_b}{\rho_w}=\frac{w_{\text {air }}}{w_{\text {air }}-w_{\text {water }}}

        =\frac{250}{250-200}=5

\rho_b=5\rho_w=5000 kg/m^3

Now, \frac{\rho_b}{\rho_l}=\frac{250}{250-150}=2.5 \\

\rho_l=\frac{\rho_b}{2.5}=\frac{5000}{2.5} \Rightarrow 2000 \mathrm{~kg} / \mathrm{m}^3

Posted by

SANGALDEEP SINGH

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