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  • A boy pushes a box of mass 2 kg with a force <img alt="\vec{F}=\left ( 20 \hat{i}+10 \hat{j} \right )N" src="https://entrancecorner.codecogs.com/gif.latex?%5Cvec%7BF%7D%3D%5Cleft%20%28%2020%20%5Chat%7Bi%7D&plus;10%20%5Chat%7Bj%7D%20%5Cright%20%29N"

A boy pushes a box of mass 2 kg with a force \vec{F}=\left ( 20 \hat{i}+10 \hat{j} \right )N on a frictionless surface. If the box was initially at rest, then_______ m is displacement along the x-axis after 10 s.
Option: 1 500
Option: 2 100
Option: 3 200
Option: 4 600

Answers (1)

best_answer

\begin{array}{l} \overrightarrow{\mathrm{F}}=20 \hat{\mathrm{i}}+10 \hat{\mathrm{j}} \\ \overrightarrow{\mathrm{a}}=\frac{\overrightarrow{\mathrm{F}}}{\mathrm{m}}=\frac{20 \hat{\mathrm{i}}+10 \hat{\mathrm{j}}}{2} \Rightarrow 10 \hat{\mathrm{i}}+5 \hat{\mathrm{j}} \\ \therefore \overrightarrow{\mathrm{s}}=\frac{1}{2} \overrightarrow{\mathrm{a}} \mathrm{t}^{2}=\frac{1}{2}(10 \hat{\mathrm{i}}+5 \hat{\mathrm{j}}) \times(10)^{2} \\ \Rightarrow 50(10 \hat{\mathrm{i}}+5 \hat{\mathrm{j}}) \mathrm{m} \end{array}

\\ \therefore$ Displacement along $\mathrm{x}$ -axis $\Rightarrow 50 \times 10 \Rightarrow 500 \mathrm{~m}$ \\ $\therefore Ans. 500

Posted by

Deependra Verma

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