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A $100 \mathrm{~W}$ bulb $B_1$ , and two $60 \mathrm{~W}$ bulbs $B_2$ and $B_3,$ are connected to a $250 \mathrm{~V}$ source, as shown in the figure. Now $W_1, W_2$ and $W_3$ are the output powers of the bulbs $B_1, B_2$ and $B_3$ respectively. Then

Option: 1
$W_1>W_2=W_3$

Option: 2
$W_1>W_2>W_3$

Option: 3
$W_1<W_2=W_3$

Option: 4
$W_1<W_2<W_3$

Answers (1)

best_answer

Voltage across bulb $B_2$ will be less than that across $B_3$

$\begin{array}{ll} \Rightarrow & W_2<W_3 \\ \therefore & \text { (d) } \end{array}$

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Rakesh

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