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A bullet of mass 2 gram is having a charge of $2\mu C$ . Through what potential difference must it be accelerated, starting from rest, to acquire a speed of $10m/s$
Option: 1
5kV

Option: 2
50kV

Option: 3
5V

Option: 4
50V

Answers (1)

best_answer

By using $1/2mv^2= QV$

$1/2 \times 2 \times10^{-3} \times10^2=2 \times10^{-6}V$

$\Rightarrow V=50kV$

Posted by

HARSH KANKARIA

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