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A capacitor C is fully charged with voltage V0. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor \frac{C}{2}. The energy loss in the process after the charge is distributed between the two capacitors is:
Option: 1 \frac{1}{2}CV_{0}^{2}
Option: 2 \frac{1}{3}CV_{0}^{2}
Option: 3 \frac{1}{4}CV_{0}^{2}
Option: 4 \frac{1}{6}CV_{0}^{2}

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\begin{aligned} &\text { Heat loss = }\\ &H=\frac{C_{1} C_{2}}{2\left(C_{1}+C_{2}\right)}\left(V_{1}-V_{2}\right)^{2}\\ &=\frac{C \times \frac{C}{2}}{2\left(C+\frac{C}{2}\right)}\left(V_{0}-0\right)^{2}=\frac{C}{6} V_{0}^{2}\\ &H=\frac{1}{6} C V_{0}^{2} \end{aligned}

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Deependra Verma

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