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A car is moving with a constant speed of 20 \mathrm{m} / \mathrm{s} in a circular horizontal track of radius 40m. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be: (Take g = 10 \mathrm{~m} / \mathrm{s}^2 \text { ) }

Option: 1

\frac{\pi}{3}


Option: 2

\frac{\pi}{2}


Option: 3

\frac{\pi}{4}


Option: 4

\frac{\pi}{6}


Answers (1)

best_answer


\mathrm{T} \cos \theta=\mathrm{mg}   _(i)  
T \sin \theta=\frac{m v^2}{R} _(ii)
\begin{aligned} & \frac{e q(i)}{e q(i i)} ; \frac{\cos \theta}{\sin \theta}=\frac{g R}{\mathrm{v}^2} \\ & \tan \theta=\frac{\mathrm{v}^2}{\mathrm{Rg}}=\frac{400}{40 \times 10}=1 \\ & \theta=\frac{\pi}{4} \end{aligned}

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shivangi.shekhar

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