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A car of mass m is moving on a concave bridge of radius r with velocity v as shown in diagram for what value of the  reaction on the car by th bridge will be maximum 

Where \theta is angle made by vertical line 

Option: 1

0 \degree


Option: 2

90 \degree


Option: 3

30 \degree


Option: 4

45 \degree


Answers (1)

best_answer

As we have learned

Reaction of Road on Car -

Centripetal force = R-mg\ cos\theta=\frac{mv^{2}}{r}

Reaction R =mg\ cos\theta+\frac{mv^{2}}{r}

R = reaction

V=velocity

r = radius

- wherein

It is a case when car moves on a concave bridge.

 

 For any angle \theta

R = \frac{mv^2}{r}+ mg \cos \theta

Maximum value of R will be for the max value of 

\cos \theta = 1 \\ or \theta = 0 \degree \\ R = \frac{mv^2}{r} + mg

 

 

 

 

 

Posted by

Ritika Jonwal

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