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A car travelling at 40\frac{km}{hr} can be stopped at a distance of  40 m by braking. If the same car is travelling with same acceleration at 80\frac{km}{hr}  the minimum stopping distance in metres is (assuming no skidding)

Option: 1

100 m 


Option: 2

75 m 


Option: 3

160 m 

 


Option: 4

150 m 


Answers (1)

best_answer

Using , 

v^2-u^2=2as

We get:

0\ =\ u^2 - 2as

Or, S\ =\ \frac{u^2}{2a}

Or, \frac{S_1}{S_2}=\frac{{u_1}^2}{{u_2}^2}

Or, S_2=\left(\frac{{u_2}^2}{{u_1}^2}\right)S_1

Or, S_2=\left(2\right)^2\left(40\right)=160\ m

Posted by

Gautam harsolia

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