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  • A Carnot freezer takes heat from water at 00C inside it and rejects it to the room at a temperature of 270C.  The latent heat of ice is 336×103 J kg

A Carnot freezer takes heat from water at 00C inside it and rejects it to the room at a temperature of 270C.  The latent heat of ice is 336×103 J kg−1.  If 5 kg of water at 00C is converted into ice at 00C by the freezer, then the energy consumed by the freezer is close to :

Option: 1

 1.67×105 J


Option: 2

1.68×106 J


Option: 3

1.51×105 J


Option: 4

1.71×107 J

 


Answers (1)

best_answer

\begin{aligned} &\Delta \theta=m L\\ &=5 \times 336 \times 10^{3}=Q_{\text {sink} k}\\ &\frac{Q_{\sin k}}{Q_{\text {source}}}=\frac{T_{\sin k}}{T_{\text {source}}}\\ &\therefore Q_{\text {source}}=\frac{T_{\text {mown}}}{T_{\text {tink}}} \times Q_{\sin k}\\ &\therefore E=Q_{\text {source}}-Q_{\text {sink}}\\ &=Q_{\sin k}\left(\frac{T_{\text {rument}}}{T_{\text {sink}}}-1\right)\\ &=5 \times 336 \times 10^{3}\left(\frac{300}{273}-1\right)\\ &=1.67 \times 10^{5} J \end{aligned}

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