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A cell of emf 90\mathrm{V} is connected across series combination of two resistors each of 100\mathrm{\Omega } resistance. A voltmeter of resistance 400\mathrm{\Omega } is used to measure the potential difference across each resistor. The reading of the voltmeter will be:

Option: 1

\mathrm{90V}


Option: 2

45\mathrm{V}


Option: 3

80\mathrm{V}


Option: 4

40\mathrm{V}


Answers (1)

best_answer

as Resistance are same so equal division of potential.
\therefore \frac{90}{2}=45\mathrm{V}

Posted by

Ritika Kankaria

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