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A certain pressure 'P' is applied to 1 litre of water and 2 litre of a liquid separately. Water gets
compressed to 0.01% whereas the liquid gets compressed to 0.03%. The ratio of Bulk modulus of
water to that of the liquid is  \frac{3}{x} The value of x is ________.

 

Option: 1

1


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Bulk Modulus   =\mathrm{V} \frac{\mathrm{dP}}{\mathrm{dV}}

\begin{aligned} & \frac{(\mathrm{B})_{\text {water }}}{(\mathrm{B})_{\text {liquid }}}=\frac{\mathrm{V} \mathrm{dP} / \mathrm{dV}}{\mathrm{V} \mathrm{dP} / \mathrm{dV}}=\frac{\mathrm{dP} / 0.01}{\mathrm{dP} / 0.03} \\ & \therefore \frac{(\mathrm{B})_{\text {wamer }}}{(\mathrm{B})_{\text {liquid }}}=\frac{0.03}{0.01}=\frac{3}{1} \\ & \frac{(\mathrm{B})_{\text {water }}}{(\mathrm{B})_{\text {liquid }}}=\frac{3}{1} \end{aligned}

\therefore On comparing with  \frac{3}{x} , The value of “x” will be “1’.

 

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Rishi

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