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  • A charge particle is accelerated through a Potential difference of 12 KV and acquires a speed of  <img alt="1.0 \times 10^6 \mathrm{~m} / \mathrm{s}" src="https://entrancecorner.oncodecog

A charge particle is accelerated through a Potential difference of 12 KV and acquires a speed of  1.0 \times 10^6 \mathrm{~m} / \mathrm{s}. It is then injected Perpendicularly into a magnetic field of Strength  0.2 T. Find the radius of the circle described by it.

 

Option: 1

12 cm


Option: 2

14 cm


Option: 3

10 cm


Option: 4

none of these


Answers (1)

best_answer


R=\frac{m v}{q B} \\

q\times 12 \times 10^3=\frac{1}{2} m\left(10^6\right)^2 \\

\frac{m}{q}=24 \times 10^{-9} \\

\Rightarrow R=\frac{24 \times 10^{-9} \times 10^6}{0.2} \\
           =12 \mathrm{~cm} \\
 

Posted by

HARSH KANKARIA

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