Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A charge q is placed at the centre of the line joining two equal charger Q. If the system of charges be in equilibrium, then find minimum value of charge a from the options given - (e - charge of a

A charge q is placed at the centre of the line joining two equal charger Q. If the system of charges be in equilibrium, then find minimum value of charge a from the options given - (e - charge of an electron)

Option: 1

e


Option: 2

2e


Option: 3

4e


Option: 4

8e


Answers (1)

best_answer

As charge q is at the centre of the charges Q and Q, so it remains in equilibrium for any value of q. For a to be in equilibrium.
\mathrm{\begin{aligned} & \vec{F}_{Q Q}+\vec{f}_{Q Q}=0 \\ & \vec{F}_{Q Q}=-\vec{f}_{Q Q} \\ & \frac{Q Q}{l^2}=\frac{Q q}{\left(\frac{l}{2}\right)^2} \\ & q=-\frac{Q}{4} \end{aligned} }                        

As minimum value of charges can be \mathrm{\pm e, } so a Should be 4e.

Posted by

vinayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question