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A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is $9.6\times 10^{-16}kg$ , the charge on it and excess number of electrons on the particle are respectively $(g=10\, m/s^{2})$

Answers (1)

Charge of the particle is given by

qE = mg or $q= \frac{mg}{E}$

Posted by

Satyajeet Kumar

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