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  • A child of mass 5 kg is going round a merry-go-round that makes 1 rotation in 3.14 s. The radius of the merry-go-round is 2 m. The centrifugal force on the child will be

A child of mass 5 kg is going round a merry-go-round that makes 1 rotation in 3.14 s. The radius of the merry-go-round is 2 m. The centrifugal force on the child will be

Option: 1

40 N


Option: 2

100 N


Option: 3

80 N


Option: 4

50 N


Answers (1)

best_answer

Given, m = 5kg, R = 2 m

time t for 1 rev = 3.14 sec or \pisec

\theta for 1 rev = 2 \pi rad

Therefore    \omega=\frac{\theta}{t}=\frac{2 \pi}{\pi}=2 \mathrm\, \, \, \, {rad} / \mathrm{s} 

centrifugal force F= mR\omega^{2}

orF=5\times 2\times 2^{2}F=5\times 2\times 2^{2}=20NF=5\times 2\times 2^{2}=40N

Posted by

shivangi.shekhar

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