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A circle   C and  the  circle \mathrm{x^2+y^2=1}  are   orthogonal and  have  radical  axis  parallel to y-axis, then  C can be

Option: 1

\mathrm{x^2+y^2+x+1=0}


Option: 2

\mathrm{x^2+y^2+1=y}


Option: 3

\mathrm{x^2+y^2-1+x=0}


Option: 4

none of these


Answers (1)

best_answer

(A) The  radical axis  of the  circle \mathrm{x^2+y^2=1}  and  the  circle  given  in

(A)  is x = -2 , which  is  | |  to y-axis

(B)  is  y =2, which  is  | |  to x-axis 

(C)  is x = 0, which  is  y-axis 

The radical  axis   with  circle  in (A)  | |  to  y-axis  and  the  given circle intersect circle given  in A orthogonally. 

 

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