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A circle of radius a with both coordinates of its centre positive, touches the axis of \mathrm{x} and the straight line \mathrm{3 y=4 x}. then its equation is

Option: 1

\mathrm{x^{2}+y^{2}-4 a x-2 y-4 a^{2}=0}


Option: 2

\mathrm{x^{2}+y^{2}-4 a x-2 a y+4 a^{2}=0}


Option: 3

\mathrm{x^{2}+y^{2}+4 a x+2 a y-4 a^{2}=0}


Option: 4

none of these


Answers (1)

best_answer

 Since it touches \mathrm{x}-axis, ordinate of its centre \mathrm{= }  radius

\mathrm{\Rightarrow(\mathrm{h}, \mathrm{a}) }  where both \mathrm{\mathrm{h} } and a positive

Now apply condition of tangency with \mathrm{3 y=4 x }.

Hence (B) is the correct answer.

Posted by

Devendra Khairwa

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