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A circle \mathrm{S} of radius \mathrm{' a ' }is the director circle of another circle \mathrm{ S_1 . S_1} is the director circle of circle \mathrm{S_2} and so on. If the sum of the radii of all these circles is 2 , then the value of \mathrm{a} is
 

Option: 1

\mathrm{2+\sqrt{2}}

 


Option: 2

2-\sqrt{2}
 


Option: 3

2-\frac{1}{\sqrt{2}}
 


Option: 4

2+\frac{1}{\sqrt{2}}


Answers (1)

best_answer

Radius of circle \mathrm{S=a}

Radius of circle \mathrm{S_1=\frac{a}{\sqrt{2}}}
Radius of circle \mathrm{S_2=\frac{a}{(\sqrt{2})^2}} and so on.

\mathrm{\therefore } sum of radii \mathrm{=a+\frac{a}{\sqrt{2}}+\frac{a}{2}+\frac{a}{2 \sqrt{2}}+\ldots . . }

\mathrm{ =\frac{a}{1-\frac{1}{\sqrt{2}}}=2 }

\mathrm{ \Rightarrow a=2 \left(1-\frac{1}{\sqrt{2}}\right)=2-\sqrt{2} \\ }

Hence option 2 is correct.




 

Posted by

Sanket Gandhi

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