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A circle of radius unity touches the co ordinate axes in the first quadrant. If the circle makes one complete rotation on y – axis along the positive direction then its equation in new position is 

 

Option: 1

\mathrm{\quad(x+1)^2+(y-1-2 \pi)^2-1=0}

 


Option: 2

\mathrm{\mathrm{x}^2+(y-1+2 \pi)^2-1=0}
 


Option: 3

\mathrm{\quad(x-1)^2+(y-1-2 \pi)^2-1=0}
 


Option: 4

None of these
 


Answers (1)

best_answer

The centre of the circle in new position is \mathrm{(1,1+2 \pi)} Therefore, the equation of the circle in new position is \mathrm{(x-1)^2+(y-1-2 \pi)^2=1^2}

Hence option 3 is correct.

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