A coffee shop has 20 different flavors of tea, including 6 black, 8 green, and 6 herbal teas. In how many ways can a customer select a set of 10 teas, where the set consists of exactly 3 black teas, 4 green teas, and 3 herbal teas, and no two teas of the same type can be adjacent in the selection?45,360
22,600
33,600
66,400
45,600
To solve this problem, we can break it down into multiple steps.
Step 1: Selecting the black teas
Since we need exactly 3 black teas in the set, we can select them in C(6, 3) = 20 ways.
Step 2: Selecting the green teas
Now, we have 10 - 3 = 7 teas remaining to be selected. Since we need exactly 4 green teas, we can select them in C(8, 4) = 70 ways.
Step 3: Selecting the herbal teas
We now have 7 - 4 = 3 teas remaining to be selected. Since we need exactly 3 herbal teas, we can select them in C(6, 3) = 20 ways.
Step 4: Arranging the selected teas
Now that we have selected the required number of teas from each category, we need to arrange them in a way that no two teas of the same type are adjacent.
Firstly, we can arrange the black teas in ways to ensure they are not adjacent.
Next, we can arrange the green teas in ways to ensure they are not adjacent.
Lastly, we can arrange the herbal teas in ways to ensure they are not adjacent.
Step 5: Combining the steps
To get the total number of ways, we multiply the results from all the steps together:
Therefore, a customer can select a set of 10 teas, consisting of exactly 3 black teas, 4 green te 3 herbal teas, where no two teas of the same type are adjacent, in the calculated total ways.
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