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  • A coil has an inductance of 0.7 H and is joined in series with a resistance of 220 . When an alternative emf of 22

A coil has an inductance of 0.7 H and is joined in series with a resistance of 220\Omega . When an alternative emf of 220 V at 50 cps is applied to it, then the wattless component of the current in the circuit is:

Option: 1

5 A


Option: 2

0.5 A


Option: 3

0.7 A


Option: 4

7 A


Answers (1)

best_answer

\mathrm{ \begin{aligned} & \tan \phi=\frac{X_L}{R}=\frac{\omega L}{R}=\frac{2 \pi \times 50 \times 0.7}{220}=1 \\ & \Rightarrow \phi=45^{\circ} \text { and } Z=\sqrt{R^2+X_L^2}=\sqrt{220^2+220^2}=220 \sqrt{2} \Omega \end{aligned}}

Wattless component of current = \mathrm{I_V \sin \phi }

\mathrm{=\frac{E_v}{Z} \sin 45^{\circ}=\frac{220}{220 \sqrt{2}} \times \frac{1}{\sqrt{2}}=0.5 \mathrm{~A} }

Posted by

Nehul

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