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A coil of inductance 200 mH and resistance 2\; \Omega is connected to a source of voltage 2 V. The current  reaches half of its steady state value in
 

Option: 1

0.2


Option: 2

0.5


Option: 3

0.3

 


Option: 4

0.7


Answers (1)

best_answer

The correct option is (4)

\begin{aligned} &i=i_{0}\left(1-e^{-t / t}\right) \\ &\tau=\frac{L}{R}=\frac{200 m H}{2}=1 \\ &\frac{i_{0}}{2}=i_{0}\left(1-e^{-t / 1}\right) \end{aligned}

\begin{aligned} &\frac{1}{2}=e^{-t} \\ &\ln \left(\frac{1}{2}\right)=-t \ln (e) \end{aligned}

\because ln\; (2)= 0.69

t= 0.7

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shivangi.bhatnagar

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