Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A coil resistance 200 ohms and self inductance 1.0 henry has been connected to an a.c. source of frequency <img alt="\mathrm{\frac{200}{\pi }Hz}" src="https://entrancecorner.oncodecogs.com/gif

A coil resistance 200 ohms and self inductance 1.0 henry has been connected to an a.c. source of frequency \mathrm{\frac{200}{\pi }Hz}.The phase difference between voltage and current is ;

Option: 1

30^{\circ}


Option: 2

63 \degree


Option: 3

45\degree


Option: 4

75\degree


Answers (1)

best_answer

\mathrm{\begin{aligned} & \tan \phi= \frac{X_{\mathrm{L}}}{\mathrm{R}}=\frac{2 \pi \mathrm{L}}{\mathrm{R}}=\frac{2 \pi(200 / \pi) \mathrm{I}}{200}=2 \\ & \therefore \quad \phi=63^{\circ} . \end{aligned}}

Posted by

rishi.raj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: NIT Rourkela cut-offs for CSE, chemical engineering drop; last years' closing ranks
anam-khan

JEE Main 2025 Live: NTA exam city slip at jeemain.nta.nic.in soon; session 1 schedule
anam-khan

JEE Main 2025 schedule out for session 1; paper 1 from January 22

Latest Question