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  • A coin is tossed 2n times. The chance that the number of times one gets head is not equal to the number of times one gets tail isOption: 1 <img

A coin is tossed 2n times. The chance that the number of times one gets head is not equal to the number of times one gets tail is

Option: 1

\mathrm{\frac{(2 n) !}{(n !)^2} \cdot\left(\frac{1}{2}\right)^{2 n}}


Option: 2

\mathrm{1-\frac{(2 n) !}{(n !)^2}}


Option: 3

\mathrm{1-\frac{(2 n) !}{(n !)^2} \cdot \frac{1}{4^n}}


Option: 4

None of these


Answers (1)

best_answer

The required probability

             = 1 - probability of equal number of heads and tails

             \mathrm{=1-{ }^{2 n} C_n \cdot\left(\frac{1}{2}\right)^n \cdot\left(\frac{1}{2}\right)^{2 n-n}=1-\frac{(2 n) !}{(n !)(n !)}\left(\frac{1}{4}\right)^n}

Posted by

Ritika Harsh

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