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A composite parallel plate capacitor is made up of two different dielectric materials with different thickness \mathrm{ \left(t_{1} \text { and } t_{2}\right)} as shown in figure. The two different dielectric materials are separated by a conducting foil \mathrm{ F}. The voltage of the conducting foil is __________ \mathrm{V}.

Option: 1

60


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{C_2=\frac{A \varepsilon_0(4)}{1} }

\mathrm{C_1=\frac{A \varepsilon_0(3)}{(0.5)} }

\mathrm{\frac{C_1}{C_2}=\frac{6}{4}=\frac{3}{2} }

\mathrm{ \frac{V_2}{V_1}=\frac{q / c_2}{q / c_1}=\frac{3}{2}}

Let,

\mathrm{V_2=3 \mathrm{K} \quad V_1=2 \mathrm{K}}

\mathrm{V_{1}+V_{2}=5K=100v}

\mathrm{k=20\: v}

The voltage of conducting foil is \mathrm{60\: v}

Posted by

Rakesh

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