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A conducting coil has 200 turns of area = 4 m2 is plced in a constant magnetic field of strength 0.5 mT . The coil is revolving frequency 20 cycle/sec. The max. emf produced is

Option: 1

50.240 V


Option: 2

40.1 V


Option: 3

42.2 V


Option: 4

52.12 V


Answers (1)

best_answer

As we learnt ,

 

Emf produced -

\varepsilon = -\frac{Nd\phi }{dt}= NBA\omega \sin \omega t

\varepsilon =\varepsilon _{0}\sin \omega t

 

- wherein

NBA\omega = \varepsilon _{0}

 

 Emf induced , \varepsilon = \frac{-Nd\phi }{dt}

\varepsilon = NBA sin \omega t

Foe max. emf , \left | sin \omega t\right | = 1

\varepsilon _{max} = NBA\omega = NBA 2 \pi f

\varepsilon _{max} = 200 x 0.5 x 10-3 x 4 x 2 x \pi x 20

\varepsilon _{max} = 50.24 V

 

Posted by

Gautam harsolia

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