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A conducting sphere of radius R is given a charge q and a point charge +Q is placed at a distance d from its centre as shown in figure. Electric potential at point P is

Option: 1
$\frac{1}{4\pi \varepsilon _{0}}\left ( \frac{Q}{b}+\frac{q}{R} \right )$

Option: 2
$\frac{1}{4\pi \varepsilon _{0}}\left ( \frac{Q}{d}+\frac{q}{R} \right )$

Option: 3
$\frac{1}{4\pi \varepsilon _{0}}\frac{q}{R}$

Option: 4
$\frac{1}{4\pi \varepsilon _{0}}\frac{Q}{b}$

Answers (1)

best_answer

Answer (2)

$V_{p}=V_{c}$

$V_{c}=\frac{kQ}{d}+\frac{kq}{R}$

Posted by

shivangi.bhatnagar

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