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A conductor of length l and mass m is placed along the east-west line on a table. Suddenly a certain amount of charge is passed through it and it is found to jump to a height h. The earth's magnetic induction is B. The charge passed through the conductor is

Option: 1

\mathrm{\frac{1}{B m g h} }


Option: 2

\mathrm{\frac{\sqrt{2 g h}}{B l m} }


Option: 3

\mathrm{\frac{\mathrm{gh}}{\mathrm{B} l \mathrm{m}} }


Option: 4

\mathrm{\frac{m \sqrt{2 g h}}{B l}}


Answers (1)

best_answer

\mathrm{i}=\frac{\mathrm{q}}{\mathrm{dt}} \\

\mathrm{\mathrm{v}=\sqrt{2 \mathrm{gh}} \\ }

\mathrm{ \mathrm{m} \cdot \sqrt{2 \mathrm{gh}}=\mathrm{F} \cdot \mathrm{dt} }

\mathrm{ \mathrm{m} \cdot \sqrt{2 \mathrm{gh}}=\mathrm{i} / \mathrm{Bdt}=\frac{\mathrm{q}}{\mathrm{dt}} l \mathrm{Bdt} \\ }

\mathrm{ \mathrm{q}=\frac{\mathrm{m} \sqrt{2 \mathrm{gh}}}{\mathrm{B} l} }

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Ritika Harsh

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