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A cubical box of steel of each equal to 1 is floating on mercury in vessel. The densities of steel and mercury are \rho_s\ and\ \rho_m. The height of the block above the mercury level is given by-

Option: 1

l(1+\frac{\rho_s}{\rho_m})


Option: 2

l(1-\frac{\rho_s}{\rho_m})


Option: 3

l(1+\frac{\rho_m}{\rho_s})


Option: 4

l(1-\frac{\rho_m}{\rho_s})


Answers (1)

best_answer

\\f_i=\frac{\rho_{solid}}{\rho_{liquid}}=\frac{\rho_s}{\rho_m}\\\\ \therefore h_i=\frac{\rho_s}{\rho_m}.l\\\\ Height\ above\ the\ mercury\ level=\frac{\rho_s}{\rho_m}.l

                                                                        =(1-\frac{\rho_s}{\rho_m}).l

Posted by

Ritika Kankaria

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