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A current 3.5A when passed for 4 hrs through a molten salt, deposits 21.85g of metal {atomic weight =182}. Find the value of n.

Option: 1

4


Option: 2

2


Option: 3

6


Option: 4

1


Answers (1)

best_answer

\mathrm{ i=3.5 \mathrm{~A} \\ }

\mathrm{ t=4 \mathrm{hrs}=4 \times 60 \times 60 \mathrm{~s} \\ }

\mathrm{ W_m=21.85 \mathrm{~g} \quad A=182 }

\mathrm{ \text { By } Eq \text { W } \quad=\frac{E i t}{F} \\ }

                      \mathrm{ W=\frac{A i t}{n F} \\ }

                        \mathrm{ n=\frac{A \times i \times t}{W F} }

\mathrm{ n=\frac{182 \times 3.5 \times 4 \times 60 \times 60}{21.85 \times 96500} }

\mathrm{ n=4 }

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HARSH KANKARIA

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